Reading .csv with dlmread? (I'm doing something wrong)
6 ビュー (過去 30 日間)
古いコメントを表示
I'm trying to read this CSV file, attached below. I tried:
x = dlmread('tse2001to2020.csv',',',2,1)
Because I'm trying to skip the header, but it gives me this error message:
Error using dlmread (line 147)
Mismatch between file and format character vector.
Trouble reading 'Numeric' field from file (row number
1, field number 3) ==>
/4/2002,12,4,2002,07:32:16,142,Total,1.024,2:04:00 AM\n
Error in HW7Prob3 (line 1)
x = dlmread('tse2001to2020.csv',',',
What am I missing here?
0 件のコメント
採用された回答
Image Analyst
2018 年 5 月 24 日
It won't work because you have strings in the lines. You can use readtable() though:
filename = 'tse2001to2020.csv';
t = readtable(filename)
4 件のコメント
Image Analyst
2018 年 5 月 24 日
I think you can but you're have to call it at least twice - basically send in row and column inputs but avoid the string column, where the string it 'Total'.
By the way, you're supposed to tag homework as homework so no one gives you the solution directly, which could get you in trouble if you turned in that solution as your own work. I've added the tag for you to help you avoid that problem.
その他の回答 (0 件)
参考
カテゴリ
Help Center および File Exchange で Text Files についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!