about the base vector Clause
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Hi ! ,
i'm a student and i from Turkey.. I'm doing my homework (linear algebra ) and i did not some questions.
For example : "a = [1,3;1,-1]' Which is to sentence the base vector for R2(the square) ?
How i do ? Please Help me this. Thank you
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Walter Roberson
2012 年 6 月 2 日
This seems to be a mathematics theory question rather than a MATLAB question.
You appear to be asking how to find the basis vector for something. There is not just one unique set of basis vectors for a space.
For example, [1 0 0], [0 1 0], [0 0 1] is one basis set for R3, but so is [1 0 0], [0 1 0], [0 0 k] for all constants k that are real valued and non-zero. There is an infinite number of solutions, so you cannot numerically solve to find all basis sets for R3 (not in any finite time period.)
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その他の回答 (1 件)
alper
2012 年 6 月 3 日
7 件のコメント
Walter Roberson
2012 年 6 月 3 日
The only MATLAB tools appears to be part of the Symbolic Toolbox
http://www.mathworks.com/help/toolbox/mupad/linalg/basis.html
These tools require that you provide a set of spanning vectors. Creating the spanning vectors is your real problem: once you have spanning vectors the transformation is routine.
There are an infinite number of spanning vectors. MATLAB does not have any tools to choose spanning vectors for you. Not unless you want to use rand() to create random vectors and check to see whether the random choices work.
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