How does OR work in an IF statement?
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I want the IF statement to check the value of 'Highest_value_month' and give 'Days' a value based on that, yet 'Days' always gets the value 31. As far as I know the syntax for OR is '||'. So why doesn't my IF statement work?
Highest_value_month = 6;
if Highest_value_month == 1 || 3 || 5 || 7 || 8 || 10 || 12
Days = 31;
elseif Highest_value_month == 2
Days = 28;
else
Days = 30;
end
The code is simplified in this case but it is essentially the same.
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採用された回答
Rik
2018 年 5 月 11 日
Because each is treated as separate test. Therefor you will need to use something like the line below. You could also use switch and case (see second example).
if Highest_value_month == 1 || ...
Highest_value_month == 3 || ...
Highest_value_month == 5 || ...
Highest_value_month == 7 || ...
Highest_value_month == 8 || ...
Highest_value_month == 10 || ...
Highest_value_month == 12
Days = 31;
end
or with switch:
switch Highest_value_month
case {1,3,5,7,8,10,12}
Days = 31;
case 2
Days = 28;
otherwise
Days = 30;
end
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その他の回答 (1 件)
KSSV
2018 年 5 月 11 日
編集済み: KSSV
2018 年 5 月 11 日
Highest_value_month = 6;
val = [1 3 5 7 8 10 12] ;
if intersect(Highest_value_month,val)
Days = 31;
elseif Highest_value_month == 2
Days = 28;
else
Days = 30;
end
OR
Highest_value_month = 12;
val = [1 3 5 7 8 10 12] ;
if ismember(Highest_value_month,val)
Days = 31;
elseif Highest_value_month == 2
Days = 28;
else
Days = 30;
end
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