iteration chaotique
1 回表示 (過去 30 日間)
古いコメントを表示
hello i need a matlab code that can be able to give me us output positiv intgers from that are included in[1,128] for X and Y but [1,28] for Z , i have this chaotic code but i can't arrive to put a candition that give positiv integers from this intervals:
X=8; K=50; % X: la clé, K: Nombre d’itérations
for i=1:K
X=4*X*(1-X); % itération de la Carte logistique
Y=4*X*(1-X);
Z=4*Y*(1-Y);
end
Please help me if you can.Thanks
採用された回答
per isakson
2012 年 5 月 21 日
Run this function with start value for X in the interval (0,1).
function cssm()
X=0.5325; K=100; % X: la clé, K: Nombre d’itérations
figure
plot3( 1, 1, 1 )
hold on
plot3( -1, -1, -1 )
for i=1:K
X=4*X*(1-X); % itération de la Carte logistique
Y=4*X*(1-X);
Z=4*Y*(1-Y);
% fprintf( '%15f%15f%15f\n', X, Y, Z )
plot3( X, Y, Z, 'd' )
pause( 0.02 )
end
end
0 件のコメント
その他の回答 (1 件)
Walter Roberson
2012 年 5 月 21 日
If X and Y are currently positive integers, then under what circumstances can X or Y stop being a positive integer in the code?
If X is a currently a positive integer but Y is not a positive integer, then under what circumstances would X continue to be a positive integer and Y would become a positive integer? Likewise for X not currently positive integer but Y being positive integer.
If neither X nor Y are currently positive integer, then under what circumstances can both become positive integers?
Once you have gone through that analysis, you should be in shape for figuring out the circumstances under which X, Y and Z all become positive integers.
1 件のコメント
参考
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!