How to solve this error?
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g=cat(4,A1,C,len,A1);
This command gives no error for
C=>> C
C(:,:,1,1) =
Columns 1 through 6
'42' '83' '1e' 'c2' '21' '77'
Columns 7 through 12
'74' '24' '4b' '72' '21' 'b7'
Columns 13 through 16
'84' 'd0' 'd4' '9c'
C(:,:,1,2) =
Columns 1 through 6
'e3' 'aa' '21' '2f' '2c' '02'
Columns 7 through 12
'a4' 'e0' '35' 'c1' '7e' '23'
Columns 13 through 16
'29' 'ac' 'a1' '2e'
C(:,:,1,3) =
Columns 1 through 6
'21' 'd5' '14' 'b2' '54' '66'
Columns 7 through 12
'93' '1c' '7d' '8f' '6a' '5a'
Columns 13 through 16
'ac' '84' 'aa' '05'
C(:,:,1,4) =
Columns 1 through 6
'1b' 'a3' '0b' '39' '6a' '0a'
Columns 7 through 12
'ac' '97' '3d' '58' 'e0' '91'
Columns 13 through 16
'47' '3f' '59' '85'
But when I change the C to this input:
C=>> Cipher
Cipher(:,:,1,1) =
'9' '1'
'7' '8'
'6' '4'
'5' '1'
'2' '7'
'9' '8'
'F' '8'
'A' '9'
'B' 'C'
'6' '2'
'D' '9'
'D' 'D'
'4' '8'
'0' 'B'
'7' 'D'
'4' '4'
Cipher(:,:,1,2) =
'0' '4'
'3' 'A'
'E' '3'
'5' '5'
'B' 'F'
'A' '3'
'C' '5'
'3' '2'
'3' '7'
'D' 'B'
'3' 'C'
'F' '3'
'E' 'F'
'4' '9'
'F' 'D'
'E' '1'
Cipher(:,:,1,3) =
'A' '4'
'0' '8'
'2' '5'
'0' '7'
'B' 'E'
'5' '8'
'C' '7'
'C' 'B'
'9' '8'
'E' '3'
'4' '8'
'D' 'C'
'C' '3'
'9' '6'
'A' '9'
'6' 'F'
Cipher(:,:,1,4) =
'A' '3'
'3' '0'
'7' '2'
'A' 'A'
'8' 'E'
'3' '3'
'A' '0'
'E' '7'
'1' 'C'
'E' 'B'
'E' '5'
'D' 'B'
'A' 'C'
'7' '5'
'8' 'B'
'7' '7'
I get an error stating:
Error using cat
Dimensions of matrices being concatenated are
not consistent.
Error in tryyy (line 154)
g=cat(4,A1,Cipher,len,A1);
What must be done?
A1- 1x16 cell
Cipher- 4d cell
C-4d cell
len-1x16 cell
Can sombody help me?
0 件のコメント
採用された回答
Walter Roberson
2018 年 3 月 14 日
C(:,:,1,4) and others are 1 x 16
Cipher(:,:,1,4) and others are 16 x 2
At the very least you need to transpose the items to 2 x 16. There might still be a problem compared to 1 x 16 but you should get further.
その他の回答 (1 件)
Image Analyst
2018 年 3 月 14 日
A1,Cipher,len, and A1 must all be the same data class and size to concatenate them. They can't be a mixture of sizes like you have. You can't concatenate a 1-D array to a 4-D array like you tried.
3 件のコメント
Image Analyst
2018 年 3 月 14 日
Cell arrays are just a special kind of array (See the FAQ), but they behave like regular arrays in many ways, like concatenating. If you don't believe me, just try to do the same thing with ordinary double arrays and see what happens:
A1 = ones(1, 16); %- 1x16 cell
Cipher = ones(16,16,16,16); %- 4d cell
C = ones(16,16,16,16); %-4d cell
len = ones(1, 16); %-1x16 cell
g=cat(4,A1,Cipher,len,A1)
You see -- the same error. Also, see Walter's answer below.
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