Find highest third of values in dateset?
6 ビュー (過去 30 日間)
古いコメントを表示
WaveHeight=[3 1 5 2 3.1 6 5.5 3 2.5];
We need to find the highest 1/3:
HighestThird=[6 5.5 5]
But what if we what a function that will calculate the mean of the heights 1/3 of WaveHeight with the length of WaveHeight being a variable which may be large?
Please see my comment in this linked post How to determine significant wave height from time series data in Matlab
E.g.
WaveHeight=randi(1000,1,1000);
HighestThird=
1 件のコメント
Adam
2018 年 1 月 12 日
編集済み: Adam
2018 年 1 月 12 日
"calculate the mean of the heights 1/3 of WaveHeight"
I don't understand what this means. What is it you want to take the mean of and what is it you want 1/3 of?
Since you are starting your own question here it makes sense to include your information here rather than reference a comment in another question with more information than this one. There is no guarantee that independent question (or the answer to which you replied) will not get deleted.
採用された回答
Star Strider
2018 年 1 月 12 日
編集済み: Star Strider
2018 年 1 月 12 日
One approach is to use the sort function:
WaveHeight=[3 1 5 2 3.1 6 5.5 3 2.5];
[Waves,Idx] = sort(WaveHeight, 'descend');
HighestThird = WaveHeight(Idx(1:fix(numel(Idx)/3)))
HighestThird =
6 5.5 5
also:
HighestThird = Waves(1:fix(numel(Idx)/3))
with the same result.
0 件のコメント
その他の回答 (0 件)
参考
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!