フィルターのクリア

Changes in vectors

1 回表示 (過去 30 日間)
Cillian
Cillian 2012 年 5 月 7 日
Hello again.
This is perhaps more a logic question,
If I got measure points at the time t is wrong, and the correct ones is in a vector L_New that has 10 x 1.
How do I do to change the wrong measure points in L to be correct?
I know that I have not post my attempt, but this is more a "thinking" question.
Anyhow, I would be please if someone can tell me how it works.
Best Regards Cillian

採用された回答

Sean de Wolski
Sean de Wolski 2012 年 5 月 7 日
This sounds like you may eventually want to interpolate. Do do this, in this case, look into interp1. If you provide us with a small set of sample data we might be better able to help you.
  2 件のコメント
Cillian
Cillian 2012 年 5 月 8 日
L =[0:10];
L_New =[0:10]';
yi = interp1(L,L_New,'nearest')
% The question is not so clear about if L have the same size or a different size.
Cillian
Cillian 2012 年 5 月 10 日
Ops, I forgot to add the results:
yi =
NaN
0
1
2
3
4
5
6
7
8
9

サインインしてコメントする。

その他の回答 (1 件)

Stefan
Stefan 2012 年 5 月 7 日
Are the measure points located in a vector with the same size like L_New? Or do you have more values?
Same size: Why do you not copy L_New? L=L_New;
Different size: you have to find first the wrong values in L, before you can compare them to L_New and exchange them.
  1 件のコメント
Cillian
Cillian 2012 年 5 月 8 日
Sorry, I don't know. The question is not so clear about if L have the same size or a different size.

サインインしてコメントする。

カテゴリ

Help Center および File ExchangeLogical についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by