フィルターのクリア

How to plot Message Signal using MATLAB ?? (Quick Question Need Help)

1 回表示 (過去 30 日間)
PG
PG 2012 年 4 月 23 日
Hi,
I have an output for a FM transmitter in the form:
y(t) = cos ( 2*pi*t + 2*pi (integral from 0,t of m(tau) dtau ) )
I need to create a message signal of the following:
m_1(t) =
{
1 when cos(t) >= 0
-1 when cos(t) < 0
}
I need to create the message signal above in MATLAB and then find the corresponding FM signal.
However, I am unclear on how to graph the message signal.. Can you please show me how?
Thank you.

採用された回答

Richard Brown
Richard Brown 2012 年 4 月 23 日
First, note that the integral of the message will be zero up to any multiple of 2*pi. The integral will then be a piecewise linear function that only requires evaluating on [0,2*pi). It's straightforward to do this by hand
pp = interp1([0, pi/2, 3*pi/2, 2*pi], [0, pi/2, -pi/2, 0], 'linear', 'pp');
int_m = @(t) ppval(pp, mod(t, 2*pi));
Then a plot of your FM signal will be
fplot(@(t) cos(2*pi*t) + 2*pi*(int_m(t)), [0 20])

その他の回答 (2 件)

Richard Brown
Richard Brown 2012 年 4 月 23 日
m_1 = @(t) 2*(cos(t) >= 0) - 1
t = linspace(0, 100);
stairs(t, m_1(t))
  3 件のコメント
Richard Brown
Richard Brown 2012 年 4 月 23 日
No, don't do that, it will be horrible!! (not wrong, just horrible)
See new answer below
PG
PG 2012 年 4 月 23 日
Well the question asks to find the corresponding FM signal for frequency = 1 in the equation
FM transmitter:
y(t) = cos(2pi*t + 2pi(frequency) * integral (0 to t) of m(tau) dtau
so how would i do that?

サインインしてコメントする。


Walter Roberson
Walter Roberson 2012 年 4 月 23 日
Try a stair plot.
  1 件のコメント
PG
PG 2012 年 4 月 23 日
but m_1(t) changes value all the time, so its not constant..
it's basically a bunch of unit step functions added together but i don't know how to code that ..

サインインしてコメントする。

カテゴリ

Help Center および File ExchangeSpectral Measurements についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by