Calculating exact roots of 6th degree polynomial
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I've a fat 6x6 matrix E with symbolic variables. I'm trying to compute sqrt(eig(E'E)), ie, the singular values. The answer begins with 'root( ) etc. How do I get MATLAB to solve this 6th degree polynomial and show me more pleasing answers? Thanks a lot.
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Image Analyst
2017 年 10 月 19 日
Use roots(), not root().
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Walter Roberson
2017 年 10 月 19 日
root() is the placeholder that replaced RootOf() a couple of releases ago in the Symbolic Toolbox.
Walter Roberson
2017 年 10 月 19 日
編集済み: Walter Roberson
2017 年 10 月 19 日
Which Galois group does it belong to? Because it is not generally possible to solve for exact algebraic roots.
By the way, have you ever looked at how long the roots are just for quartics? About 12500 characters per solution when using bare symbols for the coefficients; much much longer if the coefficients are expressions as you imply is happening for you.
Suppose you managed to find a (say) million character closed form for one of your eigenvalues: realistically, what would you do with it?
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