Cell array filtering date and time using datenum
1 回表示 (過去 30 日間)
古いコメントを表示
I have a cell array that consists of dates and time in the following format '30/12/2015 15:54:30'.
Using this code
numFormat = datenum(X{:,1},'dd/mm/yyyy HH:MM:SS');
Y(:,1)= round(numFormat);
Y(:,2)= hour(numFormat)*60 + minute(numFormat);
I get the error message: Error using datenum. Too many input arguments.
0 件のコメント
採用された回答
per isakson
2017 年 10 月 8 日
編集済み: per isakson
2017 年 10 月 8 日
Replace X{:} by char(X)
>> X = {'30/12/2015 15:54:30';'30/12/2015 15:54:30';'30/12/2015 15:54:30'};
>> numFormat = datenum(char(X),'dd/mm/yyyy HH:MM:SS')
numFormat =
1.0e+05 *
7.3633
7.3633
7.3633
0 件のコメント
その他の回答 (1 件)
Peter Perkins
2017 年 10 月 13 日
Think about using datetime and duration instead of datenum:
>> dt = datetime({'30/12/2015 15:54:30';'30/12/2015 15:54:30';'30/12/2015 15:54:30'},'InputFormat','dd/MM/yyyy HH:mm:ss')
dt =
3×1 datetime array
30-Dec-2015 15:54:30
30-Dec-2015 15:54:30
30-Dec-2015 15:54:30
>> d = dateshift(dt,'start','day')
d =
3×1 datetime array
30-Dec-2015 00:00:00
30-Dec-2015 00:00:00
30-Dec-2015 00:00:00
>> t = timeofday(dt)
t =
3×1 duration array
15:54:30
15:54:30
15:54:30
0 件のコメント
参考
カテゴリ
Help Center および File Exchange で Dates and Time についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!