Error using the randi function

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Tony
Tony 2017 年 8 月 24 日
コメント済み: Jan 2017 年 8 月 27 日
Here is my code:
function EPS
Score=zeros(1,20);
X=[0,0,0,0,0,0,0,0,0,0,1,1,1,1,1,1,1,1,1,1];
for j=1:20
Dealer=X(randi(numel(X)));
if sum(X)-.5*length(X)==0
Pick=X(randi(numel(X)));
else
if sum(X)>size(X)
Pick=1;
if sum(X)<size(X)
Pick=0;
end
end
end
if Pick==Dealer
Score(j)=1;
end
X=X(X~=Dealer);
end
disp(sum(Score)/20);
end
When I run this I get an error on line 11 (Dealer variable as the for loop is line 10): Error using randi First input must be a positive scalar integer value IMAX, or two integer values [IMIN IMAX] with IMIN less than or equal to IMAX.
If I define X as I did in my code and in my command window type X(randi(numel(X))) I do not get an error.
Why is my code giving me the error if in the command window it is working?
  3 件のコメント
Walter Roberson
Walter Roberson 2017 年 8 月 24 日
Right. You have multiple equal values so X(X~=Dealer) is deleting multiple entries, all of the duplicates of Dealer. You only have two unique values in X, so after the second time you execute the line you would have deleted everything out of X.
Perhaps you should instead keep track of the random index and delete only that one item.
Tony
Tony 2017 年 8 月 26 日
Thank you guys for your help!

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採用された回答

KSSV
KSSV 2017 年 8 月 24 日
Score=zeros(1,20);
X=[0,0,0,0,0,0,0,0,0,0,1,1,1,1,1,1,1,1,1,1];
for j=1:20
idx = randi(numel(X)) ;
Dealer=X(idx);
if sum(X)-.5*length(X)==0
Pick=X(randi(numel(X)));
else
if sum(X)>size(X)
Pick=1;
if sum(X)<size(X)
Pick=0;
end
end
end
if Pick==Dealer
Score(j)=1;
end
X(idx) = [] ;
end
disp(sum(Score)/20);
  2 件のコメント
Tony
Tony 2017 年 8 月 26 日
Thanks!
Jan
Jan 2017 年 8 月 27 日
if sum(X)<size(X) is tricky: Note that size replies a vector.

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