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# What's wrong with the code?

1 ビュー (過去 30 日間)
George Ansari 2017 年 8 月 8 日

The code supposed to delete an element from B cell if corresponding P = 0. Please help me to fix it. Thanks, George.
L = [1 10 15];
L_cell = num2cell(L);
P_max = [100;150;200];
Pg = [90 150 150];
B = [1;2;3];
for k = 1:length(L)
P_d{k} = P_max*L_cell{k};
P{k}=P_d{k} - Pg';
B_cell{k} = num2cell(B);
if (P{k}(:) == 0)
B_cell{k}(:) = [];
end
end

### 回答 (1 件)

Adam 2017 年 8 月 8 日

Simple use of the debugger or even just the command line would help you solve this.
>> P{k}(:)
ans =
1410
2100
2850
This cannot be tested by equality against 0 in an if statement (or rather not in the way you would want it to be).
It isn't obvious what you want in this case, but
doc all
doc any
will solve the problem in 2 different ways depending on what logic you want, e.g.
if ( all( P{k}(:) == 0 ) )
or
if ( any( P{k}(:) == 0 ) )
##### 2 件のコメント表示 1 件の古いコメント非表示 1 件の古いコメント
Adam 2017 年 8 月 8 日
The point is though that P{k} contains 3 elements, not just one. So P == 0 does not make sense in this context.

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