I have a hypercube data with size 512 x 320 x 211. I want to divide this cube into smaller cube data size 32x32x211 and I want to get the mean value of all smaller cube data. How can I do that using Matlab? Thanks a lot.

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michio
michio 2017 年 8 月 4 日
編集済み: michio 2017 年 8 月 4 日

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You want to divide the data into smaller pieces without any overlaps? So 512 x 320 x 211 array will be divided into 160 of 32x32x211 arrays and you want mean values from each of them, correct?
You can do it in various ways, but if you have Image Processing Toolbox, blockproc function can be useful.
myfun = @(block_struct) mean(block_struct.data(:));
I2 = blockproc(I,[32 32],myfun);
where I is your hypercube data with size 512 x 320 x 211 then I2 will be 16x10 array with mean values of each divisions.

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Imran Sofianto
Imran Sofianto 2017 年 8 月 4 日

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Thank you very much for your answer, Michio. And then how to reshape again to hypercube data with consisting 211 band? It fails when I reshape to size 16x10x211. Thank you.
[x y] = size(I2); I3 = reshape(I2, [x y c];

3 件のコメント

michio
michio 2017 年 8 月 4 日
Ah, you want 16x10x211 array in the end? So the mean operation will be preformed on each slice of 512x320? In that case, the following would do the job.
myfun = @(block_struct) mean(mean(block_struct.data));
I2 = blockproc(I,[32 32],myfun);
where I is your hypercube data with size 512 x 320 x 211 then I2 will be 16x10x211 array with mean values of each divisions.
Imran Sofianto
Imran Sofianto 2017 年 8 月 4 日
That is perfect, thank you very much, Michio. It solved my problem to analyze the hypercube data. Thanks a lot.
michio
michio 2017 年 8 月 5 日
You are welcome :)

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