Find element in matrix
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Hello, I have a matrice and i whant to find if there are 2 iqual elements in diferent rows...
A =
1 2
3 5
2 4
6 1
In this case i should find the number 1 and 2. But i whant to find one at a time. Can someone help me with this? Thank´s.
1 件のコメント
Image Analyst
2012 年 4 月 6 日
A is comprised on ONLY integers, right? Else you need to consider the FAQ: http://matlab.wikia.com/wiki/FAQ#Why_is_0.3_-_0.2_-_0.1_.28or_similar.29_not_equal_to_zero.3F
採用された回答
Richard Brown
2012 年 4 月 11 日
Here's a slightly uglier way that will work. If you need the code to perform quickly, you'd obviously preallocate your arrays m and z
z = zeros(0, 2);
m = [];
for a = unique(A(:)');
[I, ~] = find(A == a);
if numel(I) == 2
m = [m a];
z = [z; setdiff(reshape(A(I, :), 1, 4), a)];
end
end
その他の回答 (3 件)
Thomas
2012 年 4 月 6 日
Try this
clear all
A = [1 2
3 5
2 4
6 1 ];
c=intersect(A(:,1),A(:,2));
for i=1:length(c)
[p(:,:),q(:,:)]=find(A==c(i));
l=A(p(:),:);
m=unique(l)';
z(i,:)=m(m~=c(i));
end
c % common elements 1 and 2
z % elements associated with 1=2,6 and 2=1,4
Output will be
c =
1.00
2.00
z =
2.00 6.00
1.00 4.00
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