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Creating a matrix where the entry in the second column is (weakly) less than the entry in the first column
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Hello,
I would like to create a matrix where the entry in the second column is less than the entry in the first column:
A
= [ 1 0;
1 1;
2 0;
2 1;
2 2]
I can write loops but I would think there should be more efficient way. Please advise.
1 件のコメント
the cyclist
2017 年 6 月 5 日
You haven't been specific enough. For example, would this be OK?
A = rand(5,1);
A(:,2) = A(:,1) - pi;
I expect not.
回答 (1 件)
Image Analyst
2017 年 6 月 5 日
This will do it (one of an infinite number of ways):
A(:, 2) = A(:, 1) - 1
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