フィルターのクリア

create binary 0 and 1

3 ビュー (過去 30 日間)
Quynh tran
Quynh tran 2017 年 5 月 19 日
編集済み: James Tursa 2017 年 5 月 19 日
Dear all,
I have matrix of binary with n=5
A=[0 0 0 0 1
0 0 0 1 0
0 0 1 0 0
....
1 1 1 1 1]
but I only want to take a submatrix with 3 number 1 inside
subA=[ 0 1 1 0 1
1 0 1 0 1
0 1 1 1 0
........]
and
subB=[0 0 0 0 1
0 0 0 1 0
0 0 1 0 0
0 1 0 0 0
1 0 0 0 0
0 0 0 1 1
.....
0 1 1 0 1
1 0 1 0 1
0 1 1 1 0
........]
. Couyld you help me? Thanks

採用された回答

James Tursa
James Tursa 2017 年 5 月 19 日
編集済み: James Tursa 2017 年 5 月 19 日
subA = A(sum(A,2)==3,:);
For subB it is not entirely clear to me what you want. Do you want the rows of A arranged so that all rows with one 1 come first, then all rows with two 1's, then all rows with three 1's? Or what? E.g., this?
subB = [A(sum(A,2)==1,:);...
A(sum(A,2)==2,:);...
A(sum(A,2)==3,:);...
A(sum(A,2)==4,:);...
A(sum(A,2)==5,:)];
  2 件のコメント
Quynh tran
Quynh tran 2017 年 5 月 19 日
in subB, I want with 5 colums but number of 1 in a row is less than 3
James Tursa
James Tursa 2017 年 5 月 19 日
編集済み: James Tursa 2017 年 5 月 19 日
Your words do not match your example. Maybe a truncated version of the above?
subB = [A(sum(A,2)==1,:);...
A(sum(A,2)==2,:);...
A(sum(A,2)==3,:)];
or
subB = [A(sum(A,2)==1,:);...
A(sum(A,2)==2,:)];

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeData Types についてさらに検索

タグ

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by