How to get the original rgb image from hsv image?
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OK, so I have this image(in HSV) which i have got after cropping:

Now,I want to implement the same dimension cropping(i.e. the image width and height should be same as the above image) to my original(uncropped)rgb image,which is:

I used the following code
img1=imread('2.jpg');%this is the original rgb image
[y1,x1] = find(img1); 
xmin1 = min(x1(:));
ymin1 = min(y1(:));
xmax1= max(x1(:));
ymax1 = max(y1(:));
width1=xmax1-xmin1+1;
height1=ymax1-ymin1+1;
img2=imread('cropbin1.jpg');%this is the HSV image
[y2,x2] = find(img2); 
xmin2 = min(x2(:));
ymin2 = min(y2(:));
xmax2= max(x2(:));
ymax2 = max(y2(:));
width2=xmax2-xmin2+1;
height2=ymax1-ymin2+1;
w3=(width1-width2)/2;
h3=(height1-height2)/2;
out = imcrop(img1,[w3 h3 width2 height2]);
figure,imshow(out);
But, to my horror, the output is showing no image.
Please help.
I would like my original image to be like:

Please suggest any other way by which I can change the HSV image to a rgb image. Thanxxx.......
1 件のコメント
  Image Analyst
      
      
 2017 年 4 月 9 日
				There are so many things wrong with that code, that it's just faster to give you whole new code than to explain it to you. In the meantime, I fixed your formatting but for the future, please read this: http://www.mathworks.com/matlabcentral/answers/13205#answer_18099
採用された回答
  Image Analyst
      
      
 2017 年 4 月 9 日
        See attached solution.


2 件のコメント
  Image Analyst
      
      
 2017 年 4 月 9 日
				Not it won't. Just look at it:
xmin1 = min(x1(:));
well x1 is the number of columns multiplied by the number of color channels (3). Why? Just read http://blogs.mathworks.com/steve/2011/03/22/too-much-information-about-the-size-function/ So x1 is 12,960, NOT the number of columns in the image. It's not even an array, so doing this: x1(:) will not do what you thought it did.  Lots more problems after that.
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