C++ pointers and variables
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Dear experts,
I am trying to convert the following C++ code to a matlab code:
double buffer = 72.0;
double *pBuffer = &buffer;
t = sizeof(buffer));
Does anyone know to solve this question?
Thank you in advance.
Carlos
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Jan
2017 年 4 月 3 日
buffer = 72;
You do neither need a pointer in Matlab nor does the the size of the type matter.
4 件のコメント
Guillaume
2017 年 4 月 4 日
If you're using this filexchange sizeof you're using it incorrectly. The correct code should have been:
calllib(libstring,'SetSystemParameter',MAXIMUM_RANGE,pRecord31,sizeof('double'));
Or you could just not have bothered and pass 8 directly, since scalar double are always 8 bytes.
Note that matlab may have been clever enough to automatically make the conversion from double to void pointer, so possibly this may have been enough:
value = 72;
calllib(libstring,'SetSystemParameter',MAXIMUM_RANGE, value, 8)
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