How do i resolve the error in this code

for t=2005:2015
Cost(t+1)=(C*exp(-1*r*t));
end
I am getting an error which says In assigning A(I)=B,the number of elements in I should be equal to B

回答 (2 件)

ES
ES 2017 年 3 月 22 日

0 投票

What are you trying to achieve in this code?
What your code does is to set Cost(0), Cost (1)...Cost(2005) to 0; And Cost(2006) to C*exp(-1*r*2005),
Cost(2007) to C*exp(-1*r*2007), so on till Cost(2016) to C*exp(-1*r*2015). Is this what you expect?
What are values of C and r? Are these arrays?

2 件のコメント

Felicity Kaseke
Felicity Kaseke 2017 年 3 月 22 日
I want the code to calculate the costs for each year, r=0.05 and C is an equation given by C= CR + CP(x(1) + a0*x(2)), where a0 is a constant
ES
ES 2017 年 3 月 22 日
is C an array?

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Guillaume
Guillaume 2017 年 3 月 22 日

0 投票

The only way you can get this error is if one or both of C or r is not scalar. So what is
size(r)
size(C)
Your equation is basically creating a matrix or vector, which obviously can't be stored as a single element in Cost.

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