how do i use textscan to display strings have spaces in between ?
18 ビュー (過去 30 日間)
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Hi friends, i have used this code with textscan:
fidpw= fopen('yy.txt','rt');
format = repmat('%s ',[1 row1]);
Pat = textscan(fidpw,format );
fclose(fidpw);
i used texscan to display the columns in this file but it doesn't work well because of the space existed in between the first rows of its corresponding columns
the columns looks like :
col1={stage iiib;t3;n1;m0}
col2={stage iv;t4;n1;m1}
code output looks like:
col1={stage;stage;t3;n1;m0}
col2={iiib;iv;t4;n1;m1}
?????
is this because i used %s in textscan ???
Thanks in advance!
0 件のコメント
採用された回答
Walter Roberson
2017 年 3 月 22 日
In that situation, you should
Pat = textscan(fidpw, format, 'whitespace', '', 'delimiter', ';');
6 件のコメント
Walter Roberson
2017 年 3 月 22 日
ncol = 12;
fmt = repmat('%s', 1, ncol);
fid = fopen('Classeur1.txt', 'rt');
Pat = textscan(fid, fmt, 'Delimiter', '\t');
fclose(fid)
その他の回答 (1 件)
KSSV
2017 年 3 月 22 日
fid = fopen('my text file','r');
S = textscan(fid,'%s','delimiter','\n') ;
fclose(fid) ;
S = S{1} ;
Note that S will be a cell. You can access your required line using S{i} . Where i is your line number.
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