adding an array with steps untli the last row

Hello,

How is it possible to create an Array that starts at 0.02 and Ends at the last row of a second Array like 5x1? For example:

a=round(5,1)
a=
5
1
2
4
5

Now I want a second array with the same ammount of rows but starts with 0.02 and adds 0.02 every row like 0.02 0.04 0.06 and so on until the last row of the other array...

If I choose size the Array Counts until the last number of the other Array is reached... please help me!

[Guillaume]

Presumably,

a=round(5, 1)

is meant to be

a = randi(5, 5, 1);

[Felifa]

oh I'm sorry, I of course I ment a=rand(5,1)

Answer 1

[KSSV]

Say you want 5 values...

N = 5 ;
i = 0:N-1 ;
iwant = 0.02+i*0.02

[Guillaume]

i = 1:N;
iwant = 0.02*i;

would be simpler.

[KSSV]

Yes..yes you are right..@Guillaume

Answer 2

[Guillaume]

newarray = 0.02 * reshape(1:numel(a), size(a))

would work and produce an array/matrix the same shape of A, regardless of that shape.

[Felifa]

Oh very nice, that works perfectly :D Thank you so much!!!

[tarek rahmani]

correction: ('numel' not 'nume')

 newarray = 0.02  * reshape(1:numel(a), size(a))

[Guillaume]

Yes, thanks for noticing.

Answer 3

[tarek rahmani]

a=[min:step:max]

for ex:

 >> a=[1:0.2:2]

 a =

    1.0000    1.2000    1.4000    1.6000    1.8000    2.0000

[Felifa]

The problem here is that I am importing data from Excel from meassurements, so I don't know the size of the Array. Therefor the Version of Guillaume is the best for my problem. But thank you though!