covert 9.2532 decimal into binary

convert decimal into binary with decimal point

Answer 1

[Roger Stafford]

   function s = binstr(x)
   if ~isfinite(x)|(length(x)~=1), error('x must be a finite scalar.'),end
   b = (x<0); x = abs(x);
   s = zeros(1,53);
   [f,e] = log2(x);
   for i = 1:53
    f = 2*f;
    d = floor(f);
    f = f - d;
    s(i) = d+48;
   end
   s = ['0.' s sprintf('*2^(%d)',e)];
   if b, s = ['-' s]; end
   s = char(s);
   return

[Pratik Anandpara]

where to put 9.2532

[Pratik Anandpara]

without function file it is possible?

[Roger Stafford]

   binstr(9.2532)

[Pratik Anandpara]

still error i save this file as binstr name and at binstr(9.2532) not seen output

[Pratik Anandpara]

Undefined function 'finite' for input arguments of type 'double'.

Error in binstr (line 2) if ~finite(x)|(length(x)~=1), error('x must be a finite scalar.'),end

[Roger Stafford]

The function should generate a string which consists of binary digits with a binary point and a power of two. Write

s = binstr(9.2532)

and display the string. The string I get on my ancient computer is:

0.10010100000011010001101101110001011101011000111000100*2^4

[Pratik Anandpara]

 s=binstr(9.2532)
Undefined function 'finite' for input arguments of type 'double'.

Error in binstr (line 2) if ~finite(x)|(length(x)~=1), error('x must be a finite scalar.'),end

[Pratik Anandpara]

s=binstr(9.2532) i edit this in command window or function file

[Roger Stafford]

Change 'finite' to 'isfinite'.