how i can vectorize this code using bsxfun or meshgrid?

Hi,
I am trying to vectorize this code, but I dont know how to start it, I read the help files for both bsxfun and meshgrid but no luck. Can someone please guide how to look at this rather than giving the code. My code is working for me but i want to improve it.
s1= 50;
s2=100;
E_=zeros(s2,s2);
grid_=linspace(-2.5,2.5,s2);
tau=linspace(-pi,pi,s1);
x=cos(tau);
y=sin(tau);
cur=myfun(x,y); %returns vector
for k=1:s2
for m=1:s2
for n=1:s1
R= abs(sqrt((grid_(m)-x(n))^2+(grid_(k)-y(n))^2));
u_(n)= besselj(0,R)*cur(n);
end
E_(k,m)=abs(trapz(tau,u_));
end
end
Thanks
Turker

 採用された回答

Jan
Jan 2017 年 3 月 14 日
編集済み: Jan 2017 年 3 月 15 日

1 投票

You can replace the inner loop by:
R = abs(sqrt((grid_(m)-x) .^ 2 + (grid_(k)-y) .^ 2)); % [EDITED]: ^ to .^
u_ = besselj(0, R) .* cur;
I guess, that the abs() is not required.

4 件のコメント

ttopal
ttopal 2017 年 3 月 15 日
Thanks Jan, x and y are array. And I a calculating the distance between points one by one. When we change it like this, does R become an array?
Jan
Jan 2017 年 3 月 15 日
編集済み: Jan 2017 年 3 月 15 日
Yes, R has the same size as x and y, and u_ has also. At least if you run the improved version which uses the elementwise squaring .^2. See [EDITED]
ttopal
ttopal 2017 年 3 月 16 日
Hi Jan, it returns error as;
Assignment has more non-singleton rhs dimensions than
non-singleton subscripts
Error in testfields (line 121)
E_(k,m)=abs(trapz(tau,u_));
ttopal
ttopal 2017 年 3 月 16 日
編集済み: ttopal 2017 年 3 月 16 日
R = abs(sqrt((grid_(m)-x) .^ 2 + (grid_(k)-y) .^ 2))'; %transpoze added.
u_ = besselj(0, R) .* cur;
Now it works! Thank you Jan!

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