How to access the maximum value of the radius in rose?

Could someone help me to access to the value of the radius automatically plotted in any rose diagram? I have to say that I use Matlab 14b. Say, having the following code, how can I get the value 40?

 load sunspot.dat
theta = sunspot(:,2);
figure (222)
rose(theta,12)

Answer 1

[Star Strider]

Ask rose for two outputs. You can then plot it with polar.

The Code —

load sunspot.dat
theta = sunspot(:,2);
[t_out, r_out] = rose(theta,12);
[r_max, idx] = max(r_out)                           % Maximum Radius & Index
t_max = t_out(idx)*180/pi                           % Corresponding Angle
figure (222)
polar(t_out, r_out)

r_max =
    38

idx =
    30

t_max =
   210

[Ali Y.]

Thank you for your reply; I appreciate your help. Sorry for the miss-understanding. My problem is to get the value 40 (radius of the rose diagram) that is plotted automatically. I don't know how Matlab calculate that or how can I use figure handle to access it.

[Star Strider]

My pleasure.

It took some digging but I found a way to get the axis limits.

This works:

hr = rose(theta,12);
ghrp = hr.Parent.XLim

ghrp =
   -40    40

[Ali Y.]

Thank you so much for your help. I works fine.

Although, I have to mention that I had to break the last line of the code, since it seems Matlab (version 14b) does not support 'field of structure' in this case. Because, executing the line

 hr.Parent.XLim

gives the error "Attempt to reference field of non-structure array". So, I got the result of this line in two steps; like:

 hr = rose(theta,12);
hrp = get(hr,'parent')
rxlim = get(hrp,'XLim')

[Star Strider]

My pleasure.

The get function will work regardless of the version you are using. I thought R2014b (that introduced the new ‘Handle Graphics 2’) also introduced the structure syntax. My apologies.