New Vector

I am trying to write a for loop and generate a new vector. What notation do I need for the Syb(?) in the following code?

Syb = [];

for m =1:length(I_FinalOut)

    for n=1:length(Q_FinalOut)

        if I_FinalOut(m) > 0 && Q_FinalOut(n) > 0

            Syb(?) = 0

        elseif I_FinalOut(m) < 0 && Q_FinalOut(n) > 0

            Syb(?) = 1

        elseif I_FinalOut(m) > 0 && Q_FinalOut(n) < 0

            Syb(?) = 2

        elseif I_FinalOut(m) < 0 && Q_FinalOut(n) < 0

            Syb(?) = 3

        end

    end

end

If I use (i), then it goes through my I_FinalOut, and if I use (j) it does the Q_FinalOut. So I am not sure what notation to use to get a new vector Syb of it's own based on the if statement.

Answer 1

[Aldin]

Hi, i think you need 4 counters, in this case you code will be like this:

Syb = []; counter1 = 0; counter2 = 0; counter3 = 0; counter4 = 0; for m =1:length(I_FinalOut)

    for n=1:length(Q_FinalOut)
        if I_FinalOut(m) > 0 && Q_FinalOut(n) > 0
            counter1 = counter1 + 1;
            Syb(counter1) = 0          
        elseif I_FinalOut(m) < 0 && Q_FinalOut(n) > 0
            counter2 = counter 2 + 1;
            Syb(Syb(end)+counter2) = 1
        elseif I_FinalOut(m) > 0 && Q_FinalOut(n) < 0
            counter3 = counter3 + 1;
            Syb(Syb(end)+counter3) = 2
        elseif I_FinalOut(m) < 0 && Q_FinalOut(n) < 0
            counter4 = cpunter4 + 1;
            Syb(Syb(end)+counter4) = 3
        end
    end
end

or other solution if only on if condition is ready for processing (true):

Syb = []; counter1 = 0; counter2 = 0; counter3 = 0; counter4 = 0; for m =1:length(I_FinalOut)

    for n=1:length(Q_FinalOut)
        if I_FinalOut(m) > 0 && Q_FinalOut(n) > 0
            counter1 = counter1 + 1;
            Syb(counter1) = 0          
        elseif I_FinalOut(m) < 0 && Q_FinalOut(n) > 0
            counter2 = counter 2 + 1;
            Syb(counter2) = 1
        elseif I_FinalOut(m) > 0 && Q_FinalOut(n) < 0
            counter3 = counter3 + 1;
            Syb(counter3) = 2
        elseif I_FinalOut(m) < 0 && Q_FinalOut(n) < 0
            counter4 = cpunter4 + 1;
            Syb(counter4) = 3
        end
    end
end