How to have my array continuously expanding in a for loop?
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I have a 3x2 matrix (M). Column one is a starting location (mile markers) and column two is the ending location for that row. I want to create an array that will take every 0.1 increment between the start and end, put it in an array, and move on to the next row, BUT continue to add the elements to array instead of simply updating the array with latest span. Please see my example code below:
M = [1.0 1.5; 2.0 2.3; 1.7 2.2];
stop=length(M);
n=1;
for n = 1:stop
stuck = M(n,1):0.1:M(n,2)
end
The result is the 0.1 increment span of the last row: M = [1.7 1.8 1.9 2.0 2.1 2.2]
What I want is M = [1.0 1.1 1.2 1.3 1.4 1.5 2.0 2.1 2.2 2.3 1.7 1.8 1.9 2.0 2.1 2.2]
I have spent way too much time on this snag and any input would be appreciated!
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採用された回答
Geoff Hayes
2017 年 2 月 14 日
David - try concatenating using the square brackets
stuck = [];
M = [1.0 1.5; 2.0 2.3; 1.7 2.2];
stop=length(M);
n=1;
for n = 1:stop
stuck = [stuck M(n,1):0.1:M(n,2)];
end
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その他の回答 (2 件)
Adam
2017 年 2 月 14 日
編集済み: Adam
2017 年 2 月 14 日
You'll have to use a cell array since they will be of different lengths for each row e.g.
stuck{n} = M(n,1):0.1:M(n,2);
As an aside, don't use
length( M )
use
size( M, 1 )
instead. It is safer. Maybe you will never have a case where you only have 1 row, but if you do length will return 2 because it just gives you the longest dimension. size( M, 1 ) will always explicitly give you the number of rows.
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