Repeat a vector with increment

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John
John 2016 年 12 月 30 日
編集済み: Azzi Abdelmalek 2016 年 12 月 30 日
Given
vector a = (1:N)'; with N consecutive integers
how to generate
matrix b = [a a+1 a+2 ... a+M]; with M columns, each column incremented by one.
For example
N = 3; M = 3;
a = (1:3)';
b = [(1:3)' (2:4)' (3:5)' (4:6)'];

採用された回答

Star Strider
Star Strider 2016 年 12 月 30 日
This works:
N = 3;
M = 3;
a = (1:3)';
b = bsxfun(@plus, a, [0:M-1])
b =
1 2 3
2 3 4
3 4 5

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