How to index in an array from one cell to another cell column wise?

Help, I have an array that is 1x34; however once expanded it becomes some nx6 array. I would like to loop through each column and extract the first row then loop through the columns and extract the second row.

How would you do this or is there an easy way to do this?

[KSSV]

Not clear....in a cell there is n*6 matrix, what you want to extract from it? For one cell, tell me what you want to extract?

[liu James]

So basically, I will be doing comparisons between (bb{i}(s,1) > bb{i}(s,2) for each column and row. But I want it to loop back to the other columns and do the comparison row by row vs completing the full length of the first column. Does that make sense?

for i = 1:34 %% Find initial status in the portfolio: % 0 = hold nothing, 1 = Long asset, and % -1 = Short asset [status, qty1, qty2] = calcStatus(P,u,i);

    %%Create an order based on Donchian Trend and holding status
    caseNum = 0;
    for s=1:length(bb{i})
    if (status == 0) && (bb{i}(s,1) > bb{i}(s,2))
        % Case 1: No holding position & Open > upper band
        caseNum = 1;
        bList{i} = u{i,1};
        bQty{i} = Unit_Size;
     elseif (status == 0) && (bb{i}(s,1) < bb{i}(s,3))
        % Case 2:  No holding position & Open < lower band
        caseNum = 2;
        sList{i} = u{i,1};
        sQty{i} = Unit_Size;
end
end

Answer 1

[KSSV]

clc; clear all ;
load bb.mat ;
[m,n] = size(bb) ;
for i = 1:n
    k = bb{i}(:,1:2) ;
     % Get bb{i}(s,1) > bb{i}(s,2) indices
    idx = find(k(:,1)>k(:,2)) ;

end

I dont think the elements in first column are greater then second column in any cell.