Error using inline/subsref (line 14) Too many inputs to inline function.

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James Thiem
James Thiem 2016 年 12 月 1 日
コメント済み: James Thiem 2016 年 12 月 2 日
Greetings, my code run with error message of 'Error using inline/subsref (line 14) Too many inputs to inline function.'
This is where I used inline function.
df = vectorize(inline(get(handles.edit8,'String')))
f = vectorize(inline(get(handles.edit9,'String')))
When I run with the string of ' df(x,y) = 4.*exp(0.8.*x)-0.5.*y' and ' f(x) = (40.*exp(-x./2).*exp((13.*x)./10))./13 - (14.*exp(-x./2))./13', the code run perfectly.
However, when i run with this string ' df(x) = -2.*x.^3+12.*x.^2-20.*x+8.5' and 'f(x) = - x.^4./2 + 4.*x.^3 - 10.*x.^2 + (17.*x)./2 + 1', it has the error message.
Need help for this issue and it is very much appreciated! Thanks :)

採用された回答

Steven Lord
Steven Lord 2016 年 12 月 1 日
The way you've described the problem, it sounds like whatever is invoking the inline object will pass 2 inputs into df, but when you construct the inline in the second case it only detects one variable in the expression (using symvar) and so inline will construct an object that only accepts one input.
I strongly suggest that you use str2func to create an anonymous function instead of creating an inline object.
  1 件のコメント
James Thiem
James Thiem 2016 年 12 月 2 日
Hi Steven. Thanks for your reply.
if true
% code
endI modified the code as follows:
df =str2func(get(handles.edit8,'String'))
f = str2func(get(handles.edit9,'String'))
and my string for df and f respectively:
' @(t,y) - 2.*y + t.^2'
' @(t) (3.*exp(-2.*t))./4 - t./2 + t.^2./2 + 1./4'
My outputs are:
df =
@ @(t,y) - 2.*y + t.^2
f =
@ @(t) (3.*exp(-2.*t))./4 - t./2 + t.^2./2 + 1./4
But I got this error message:
Undefined function ' @(t,y) - 2.*y + t.^2' for input arguments of type 'double'.
It may due to the usage of df in the equation:
Error in rk3 (line 32) k1=h*df(T(j),Y(j));
Your help is much appreciated! Thanks!

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その他の回答 (1 件)

Star Strider
Star Strider 2016 年 12 月 1 日
It is difficult to determine exactly what you are doing. Your inline function takes only one input, 'String', so you can only pass one argument to it in any one call to it.

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