Use array functions, logical, and relational operators.
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Calculate the percentage of points in the positive quadrant. Assign this to the variable p. The positive quadrant is defined by having both coordinates positive. A percentage is equal to 100 times a fraction. The value should be close to 25%.
I am having a hard time with this. please help
1 件のコメント
James Tursa
2016 年 11 月 30 日
What have you done so far? What specific parts of your code are you having trouble with?
回答 (1 件)
Vishal Neelagiri
2016 年 12 月 5 日
Let us assume that you have a variable named 'data' that is an n*2 matrix where 'n' corresponds to the total number of points and the x,y coordinates of these n points are provided in their respective 2 columns. You can use the following code in order to calculate the percentage of points in the positive quadrant, store this value in 'p' and then check if this value is equal to 25:
a = 0;
for i=1:n
if (data(i,1)>0)
if (data(i,2)>0)
a = a + 1;
end
end
end
p = (a/n)*100;
if (p==25)
disp('25% of all points are in first quadrant')
end
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