Interpolation of hourly data into minutes
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Hello again, I am having a trouble with modifying my data. I have hourly data of photovoltaic production during whole year, so it's 8760 values. I need to transfer them into minute data => 525 600 values. Here is the sample of first 24 hours values. e.g. value 152.03 will be separated into 60 values of 2.53, 0 into 60x0 and so on..
0
0
0
0
0
0
0
0
0
152.03
79.284
63.47
316.18
65.074
270.32
168.44
0
0
0
0
0
0
0
0
Can you help me with this? Thank you.
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Andrei Bobrov
2016 年 11 月 10 日
編集済み: Andrei Bobrov
2016 年 11 月 10 日
here a - your hourly values.
out = kron(a,ones(60,1)/60)
その他の回答 (1 件)
Steven Lord
2016 年 11 月 10 日
A slightly smaller example that illustrates the general technique:
y = repelem(1:4, 3)/8
The output is a twelve element vector that you can think of as having four [= length(1:4)] groups of three elements where the first group contains 1/8, the second group 2/8, etc.
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