Invalid Message ID Format. Is my syntax wrong?

3 ビュー (過去 30 日間)
Mert Ayduman
Mert Ayduman 2016 年 10 月 24 日
回答済み: Marc Jakobi 2016 年 10 月 24 日
function area = areaof3ang(x1,y1,x2,y2,x3,y3)
if nargin~=6
error(message('You need to input 6 values for 3 points. As in x1,y1,x2,y2,x3,y3'));
end
area=abs((x1*(y2-y3) + x2*(y3-y1) + x3*(y1-y2))/2)
end
When I deliberately input 2 variable, it shows me this error.
Error using message
Invalid Message ID format: 'You need to input 6 values for 3 points. As in x1,y1,x2,y2,x3,y3'.
Error in areaof3ang (line 3)
error(message('You need to input 6 values for 3 points. As in x1,y1,x2,y2,x3,y3'))
What am I doing wrong?

採用された回答

Marc Jakobi
Marc Jakobi 2016 年 10 月 24 日
You do not need message() for that function.
function area = areaof3ang(x1,y1,x2,y2,x3,y3)
if nargin~=6
% this is sufficient:
error('You need to input 6 values for 3 points. As in x1,y1,x2,y2,x3,y3');
end
area=abs((x1*(y2-y3) + x2*(y3-y1) + x3*(y1-y2))/2)
end

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeEvent Functions についてさらに検索

タグ

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by