Hi,
I am unable to find the MCR installer in Matlab R2010a. Where do I find it?
Thanks,
Rohan

1 件のコメント

hassene braham
hassene braham 2016 年 6 月 21 日
hello, i have the same problem now.have you find the solution?
thank you.

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回答 (3 件)

Kaustubha Govind
Kaustubha Govind 2012 年 2 月 27 日

1 投票

If you already have MATLAB Compiler installed, type the following command to locate the MCR installer:
>> mcrinstaller
Ken Atwell
Ken Atwell 2012 年 4 月 10 日

1 投票

Rohan,
The MCR for that version of MATLAB is not available from mathworks.com. Assuming you received the compiled application from someone else, they will also need to provide the MCR to you. More information can be found at this similar question.
As-of R2012a, the MCR is available for download.

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Rohan
Rohan 2012 年 4 月 10 日
@Ken et. al.,
Thanks for your reply. I did not receive the compiled application. I am trying to build my own standalone application for distribution. I believe I need the Matlab Compiler Toolbox for the same?
I was under the impression that it is a part of the Matlab distribution but doesn't look like it. What needs to be done in order to build standalone apps.?
Thanks,
Rohan
Walter Roberson
Walter Roberson 2012 年 4 月 10 日
To build a standalone application for distribution, you need the MATLAB Compiler (directly) or MATLAB Coder. MATLAB Compiler includes the MCR you will need to distribute with your application.
Note: the terms and conditions do not allow you to make MCR available to others in an uncontrolled manner. Recipients must be individually (or corporately) authorized by you to download MCR; you cannot post it on a web site or FTP site unless it is password protected. I do not know Mathwork's reason for choosing this, but they did.

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Walter Roberson
Walter Roberson 2012 年 2 月 27 日

0 投票

It is part of the Compiler Toolbox.

2 件のコメント

Rohan
Rohan 2012 年 4 月 9 日
@Kaustubha & Walter,
Thanks for your reply. I do not have the Compiler Toolbox and mcsinstaller doesn't work. Further, it is not clear how the same can be obtained and installed.
Any help would be much appreciated.
Thanks,
Rohan
Kaustubha Govind
Kaustubha Govind 2012 年 4 月 10 日
In that case, read Ken's answer.

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