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Can anyone simplify this code please?

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jlt199
jlt199 2016 年 9 月 13 日
コメント済み: jlt199 2016 年 9 月 15 日
Morning all,
I have a problem. I'm trying to take a subset of a matrix, but not a uniform distribution. The difference between points is given in the vector phi, which I've made super long to make sure I don't reach the end of it, As you can see this vector is a 6 number repeating pattern. I've made a vector, zeta, containing the rows I would like to extract from the matrix. But, it is super clunky! Is anyone able to simplify this code for me please? I'm sure it should be possible without the loop.
phi = repmat([8.70;8.70;8.70;8.70;8.70;16.59],10,1);
% Random number generator to decide which sensor to use first
sensor = randi(6,1);
col = 1;
zeta = 1;
while col + round(phi(sensor),0) < 153
col = col + round(phi(sensor),0);
zeta = [zeta; col];
sensor = sensor + 1;
end
Many thanks
  5 件のコメント
jlt199
jlt199 2016 年 9 月 13 日
Also, my boss reads Matlab so would be good to have sophisticated looking code ;)
jlt199
jlt199 2016 年 9 月 14 日
Does no comments mean that the code is not easily simplifies and I'm ok using a loop in this context? Thanks

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TallBrian
TallBrian 2016 年 9 月 14 日
I am not sure exactly what you mean by simplify but here is some code which eliminates the looping.
LENGTH = 153;
phi = round([8.70; 8.70; 8.70; 8.70; 8.70; 16.59]);
max_reps = round(LENGTH / sum(phi)) + 1;
phi_complete = repmat(phi, max_reps, 1);
phi_offset = [1; phi_complete(randi(6,1):end)];
zeta = cumsum(phi_offset);
zeta = zeta(zeta < LENGTH);
  1 件のコメント
jlt199
jlt199 2016 年 9 月 15 日
Thanks Brian, this helps a lot

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