z=1:100; for n=1:100 f(z)=n; end
why f(z) all equals to 101 instead of 1, 2, 3...100 after running.

 採用された回答

Sean de Wolski
Sean de Wolski 2016 年 8 月 31 日

0 投票

t = zeros(1,10);
t(1:10) = 3
This is what you're doing. You're setting all of the indices (1:100) equal to n. Thus only the last iteration of the for-loop actually matters.
You probably want something like
for n = 1:100
f(n) = n;
end

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