How can I correct this error?

1 回表示 (過去 30 日間)
Yaser Alghawi
Yaser Alghawi 2016 年 8 月 9 日
コメント済み: Jan 2018 年 5 月 13 日
Write function called huge_add that adds together two positive integers of any length specified as strings using decimal notation. The single output argument is the result and it is a string as well. The inputs and output must contain digits only; no commas, spaces or any other characters are allowed. If any of these assumptions are violated by the input, the function returns the number -1.
Here is my code:
function[c]=huge_add(a1,b1)
aaa=length(a1);
bbb=length(b1);
c=0;
if isnumeric(a1) ||isnumeric(b1)
c=-1
else if ~isnumeric(a1) ||~isnumeric(b1)
for i=1:aaa
if a1(i)~='1'&& a1(i)~='2'&&a1(i)~='3'&&a1(i)~='4'&&a1(i)~='5'&&a1(i)~='6'&&a1(i)~='7'&&a1(i)~='8'&&a1(i)~='9'&&a1(i)~='0'
c=-1
end
end
for i=1:bbb
if b1(i)~='1'&&b1(i)~='2'&&b1(i)~='3'&&b1(i)~='4'&&b1(i)~='5'&&b1(i)~='6'&&b1(i)~='7'&&b1(i)~='8'&&b1(i)~='9'&&b1(i)~='0'
c=-1
end
end
end
a=a1;
b=b1;
aa=length(a);
bb=length(b);
as=(str2num(a));
bs=(str2num(b));
af=fliplr(a);
bf=fliplr(b);
if c~=-1
if aa<bb
for ii=1:aa
x(ii)=af(ii);
y(ii)=bf(ii);
z(ii)=str2num(x(ii))+str2num(y(ii));
zz{ii}=num2str(z(ii));
end
cl=fliplr(z);
rem=(b(1):b(bb-aa));
ca=[rem,cl(1):cl(end)];
else if aa>bb
for ii=1:bb
x(ii)=af(ii);
y(ii)=bf(ii);
z(ii)=str2num(x(ii))+str2num(y(ii));
zz(ii)=num2str(z(ii))
end
cl=fliplr(z);
rem=(a(1):a(aa-bb));
ca=[rem,cl(1):cl(end)];
else
for ii=1:aa
x(ii)=af(ii);
y(ii)=bf(ii);
z(ii)=str2num(x(ii))+str2num(y(ii));
zz(ii)=num2str(z(ii));
end
cl=fliplr(z);
rem=[];
ca=[rem,cl(1):cl(end)];
end
end
d=str2num([rem,fliplr(zz)])
%d=([rem,fliplr(zz)])
c=num2str(d)
end
end
end
when the arguments are long numbers such as:'387363715250650494', '2959321308593705578801966108511980929658625'
I get this error:
In an assignment A(:) = B, the number of elements in A and B must be the
same.
Error in huge_add (line 33)
zz(ii)=num2str(z(ii));
How can I fix this?

回答 (2 件)

Srishti Saha
Srishti Saha 2018 年 5 月 13 日
This works perfectly:
%problem huge add
function summa = huge_add(a,b)
if ~ischar(a) || ~ischar(b) || sum(isstrprop(a,'digit')) ~= length(a) || ...
sum(isstrprop(b,'digit')) ~= length(b)
summa = -1;
return;
end
lng = max([length(a) length(b)]);
a = [a(end:-1:1) '0'+zeros(1,lng-length(a))]; % flip and pad with zeros if necessary
b = [b(end:-1:1) '0'+zeros(1,lng-length(b))]; % flip and pad with zeros if necessary
carry = 0;
for ii = 1:lng
c = carry + str2num(a(ii)) + str2num(b(ii)) % add the digits plus the caryy
carry = c > 9; % is there carry? (0 or 1)
summa(ii) = num2str(mod(c,10)); % put the character in the result
end
if carry
summa(end+1) = '1'; % need a leading 1 if carry
end
summa = summa(end:-1:1); % flip it back
end
  2 件のコメント
Walter Roberson
Walter Roberson 2018 年 5 月 13 日
We discourage giving complete answers for homework questions.
Jan
Jan 2018 年 5 月 13 日
@Srishti Saha: When a student delivers a solution copied from a forum, this can be treated as trial to cheat. Therefore it is much better to assist the students in finding a solution by their own.
As soon as this forum degrades to a homework cheater community, it will loose its power. Please consider this. Thank you.

サインインしてコメントする。


Walter Roberson
Walter Roberson 2016 年 8 月 9 日
A few lines up from there you have
zz{ii}=num2str(z(ii));
but in this line you have
zz(ii)=num2str(z(ii));
Is zz a cell array or is it a numeric array?

カテゴリ

Help Center および File ExchangeProgramming についてさらに検索

タグ

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by