Using dsolve function to solve this equation?
4 ビュー (過去 30 日間)
古いコメントを表示
Question: Use dsolve to solve this equation: y' − y = 2 sin(t).
Below is the code I used but I do not think I am getting the right answer.
syms y(t);
y = dsolve(diff(y) == 2*sin(t)+y)
0 件のコメント
採用された回答
Star Strider
2016 年 7 月 23 日
For grins, I decided to see what a Laplace transform solution would produce:
syms s y(t) y0 Y
Lsin = laplace(sin(t));
Eqn1 = Y*(s-1) == Lsin;
Eqn2 = solve(Eqn1, Y);
Eqn3 = ilaplace(partfrac(Eqn2))
Eqn4 = simplify(Eqn3, 'steps',10)
Eqn3 =
exp(t)/2 - cos(t)/2 - sin(t)/2
Eqn4 =
exp(t)/2 - (2^(1/2)*sin(t + pi/4))/2
2 件のコメント
Star Strider
2016 年 7 月 23 日
My point is that it gives an equivalent answer to the answer dsolve returns when you simplify it. It assumes an initial condition of zero. If you want to specify an initial condition, include one:
syms y(t) y0
y = dsolve(diff(y) == 2*sin(t)+y, y(0) == y0)
y =
exp(t)*(y0 + 1) - 2^(1/2)*cos(t - pi/4)
その他の回答 (0 件)
参考
カテゴリ
Help Center および File Exchange で Calculus についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!