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Why does my for-loop nested in an if-statement not work?

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F S
F S 2016 年 7 月 20 日
コメント済み: F S 2016 年 7 月 20 日
I have an for-loop inside an if-statement nested again in another for-loop (I know sounds complicated, example below), which seems to run perfeclty, as long as until the loop is called the SECOND time. Then it gives me the error:
Index exceeds matrix dimensions.
Error in code (line 50)
imb=squeeze(B_proc(n,:,:));
Does anybody have an idea why?
Here the simplified for-if-for-loop:
k=1;
for i=2:length(proc_core)
proc=cell2mat(proc_core(i,2));
sz=size(proc);
l=sz(1);
vs=cell2mat(proc_core(i,3));
if sz(2)==512 && sz(3)==512 && vs==2.5
kl=k+l-1;
Core(k:kl,:,:)=proc;
k=k+l;
elseif vs==2.5
for n=1:length(proc)
imb=squeeze(proc(n,:,:));
imb=imresize(imb,[512 512]);
Core(k,:,:)=imb;
k=k+1;
end
end
end

採用された回答

Walter Roberson
Walter Roberson 2016 年 7 月 20 日
length(proc) is defined as:
if isempty(proc)
length = 0
else
length = max(size(proc))
end
You, however, used length(proc) as if it were defined as size(proc,1) . If one of the other dimensions of proc is bigger than the number of rows then that bigger dimension is the length.
  1 件のコメント
F S
F S 2016 年 7 月 20 日
thanks a lot! I suspected there was some other bug in there but I just couldn't find it.

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