finding the closest grid
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I have 2 variables and each of 3 discretization say for example, first variable have values (2,4,6) and second variable have (1,3,5). so out of these I can make a 9 combination which looks something like this: grid = {(2,1), (2,3), (2,5), (4,1), (4,3), (4,5), (6,1), (6,3), (6,5)}
Suppose if I have a combination (2.8, 4.2) and I would like to find the closest value out of my 9 combination for it
How can I do that ?
Thanks
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Walter Roberson
2012 年 2 月 16 日
nearestx = interp1([2,4,6], [2,4,6], comb(:,1), 'nearest');
nearesty = interp1([1,3,5], [1,3,5], comb(:,2), 'nearest');
There are other ways as well.
2 件のコメント
Walter Roberson
2012 年 2 月 17 日
The above will handle that situation as well.
var1vals = sort([2, 4, 6, 7, -3, 11, pi^2, sqrt(30)]);
var2vals = sort([1, 3, 5, 9, 1.15, 33, -5, -8]);
nearestx = interp1(var1vals, var1vals, comb(:,1), 'nearest');
nearesty = interp1(var2vals, var2vals, comb(:,2), 'nearest');
An alternative:
var1vals = sort([2, 4, 6, 7, -3, 11, pi^2, sqrt(30)]);
var2vals = sort([1, 3, 5, 9, 1.15, 33, -5, -8]);
[mindiffx, minidxx] = min(bsxfun(@(a,b) abs(a-b), comb(:,1), var1vals), [], 2);
[mindiffy, minidxy] = min(bsxfun(@(a,b) abs(a-b), comb(:,2), var2vals), [], 2);
nearestx = var1vals(minidxx);
nearesty = var2vals(minidxy);
Note that both of these approaches handle all of the combinations at the same time, if the combinations are stored in the matrix "comb" with the first column being the first variable and the second column being the second variable.
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