how i can use x(t) & ... in my program

i use this code but matlab show me an eror how i can fix this eror
also i want plot (>) with angle fee how i can do that ?
clear all
t=0;
x(t)=input('Enter X(0) =');
y(t)=input('Enter Y(0) =');
fee(t)=input('Enter Fee(0) =');
for (x(t+1)~=10)&&(fee(t+1)~=90)
t=t+1;
plot(x(t),y(t),'>');
x(t+1)=x(t)+cos(fee(t)+teta(t))+sin(teta(t))*sin(fee(t));
y(t+1)=y(t)+sin(fee(t)+teta(t))-sin(teta(t))*cos(fee(t));
fee(t+1)=fee(t)-asin((2*sin(teta(t)))/4);
end

 採用された回答

Walter Roberson
Walter Roberson 2012 年 2 月 16 日

0 投票

MATLAB does not permit the value 0 to be used as a vector index. Vector indexes must be integers 1 or greater.
Requesting '>' as the plot marker gets you a right-pointing triangle. If you want an open arrow instead, then you will need to draw in the markers yourself at each location.

その他の回答 (2 件)

behnam
behnam 2012 年 2 月 16 日

0 投票

thank you but now i receive this message : ??? Attempted to access x(2); index out of bounds because numel(x)=1.

1 件のコメント

Walter Roberson
Walter Roberson 2012 年 2 月 16 日
If, hypothetically, MATLAB allowed x(0) to be defined, then you would still have had this problem anyhow, because of your line
for (x(t+1)~=10)&&(fee(t+1)~=90)
which, besides being syntactically invalid for a "for" loop, would attempt to access x(1) at a time when only x(0) had been defined.
Your code is non-functional in such a manner that we cannot make a reasonable guess about what you were attempting to write.

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behnam
behnam 2012 年 2 月 16 日

0 投票

i mean i edited my m-file code as below :
please if possible edit my m-file into correct
clear all
t=1;
x(t)=input('Enter X(0) =');
y(t)=input('Enter Y(0) =');
fee(t)=input('Enter Fee(0) =');
plot(x(t),y(t),'>');
i=1;
if (x(t)~=10)&&(fee(t)~=90)
x(t+1)=x(t)+cos(fee(t)+teta(t))+sin(teta(t))*sin(fee(t));
y(t+1)=y(t)+sin(fee(t)+teta(t))-sin(teta(t))*cos(fee(t));
fee(t+1)=fee(t)-asin((2*sin(teta(t)))/4);
plot(x(t+1),y(t+1),'>');
t=t+1;
end

1 件のコメント

Walter Roberson
Walter Roberson 2012 年 2 月 16 日
Do you want a "while" loop instead of "if" ? If so then you would move the plot() to after the "while" and would
plot(x, y, '>')
However! See
http://matlab.wikia.com/wiki/FAQ#Why_is_0.3_-_0.2_-_0.1_.28or_similar.29_not_equal_to_zero.3F
as otherwise your loop might never terminate.

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