フィルターのクリア

How to apply for loop for cell arrays?

1 回表示 (過去 30 日間)
Ali Y.
Ali Y. 2016 年 6 月 16 日
コメント済み: Ali Y. 2016 年 6 月 16 日
I have a matrix that I want dividing it to n matrices, say n = 2, and do some operations along their lengths. The second chain of ‘for’ loops does what I need when there is one matrix, as in the case of the parent matrix (a). But I can’t apply same procedure for the two cell arrays I have.
clear all
clc
a =(1000-0).*rand(10,2)+0 ;
[r,c] = size(a) ;
mina = [1 7] ;
maxa = [6 10] ;
b = cell(numel(mina),1) ;
for o = 1:numel(mina)
b{o} = a(mina(o): maxa(o),:);
end
max_a= zeros(r,c);
for i = 1:r
for j = 1:c
max_a(i,j) = max(a(1:i,j)) ;
end
end
This following lines was what I tried before but it doesn’t work.
for u = 1:numel(mina)
b2(1:maxa(u),:) = cell2mat(b(u)) ;
for i2 = mina(u):maxa(u)
for j2 = 1:c
max_a {u} = max(b2(1:i2,j2)) ;
end
end
end
  2 件のコメント
Guillaume
Guillaume 2016 年 6 月 16 日
With your given example, can you show what the output of your last loop should be, as I've no idea what you're trying to do with it.
Guillaume
Guillaume 2016 年 6 月 16 日
Note that if you have a recent version of matlab, your first max_a is simply:
max_a = cummax(a);

サインインしてコメントする。

採用された回答

Azzi Abdelmalek
Azzi Abdelmalek 2016 年 6 月 16 日
a =(1000-0).*rand(10,2)+0
[r,c] = size(a)
mina = [1 7] ;
maxa = [6 10] ;
b = cell(numel(mina),1) ;
for o = 1:numel(mina)
b{o} = a(mina(o): maxa(o),:);
end
for k=1:numel(b)
bb=b{k};
[r,c]=size(bb);
max_a= zeros(r,c);
for i = 1:r
for j = 1:c
max_a(i,j) = max(a(1:i,j)) ;
end
end
max_b{k}=max_a
end
  1 件のコメント
Ali Y.
Ali Y. 2016 年 6 月 16 日
Thank you Azzi for the help.

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeLogical についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by