How to get multiple groups plotted with histogram?

98 ビュー (過去 30 日間)
Diemo Schwarz
Diemo Schwarz 2016 年 6 月 7 日
編集済み: the cyclist 2016 年 6 月 7 日
With hist, the columns of an input matrix would be interpreted as different data sets and the frequency bars grouped per bin:
hist(rand(20,4))
How to get this behaviour with the new histogram function that is supposed to supercede hist?
histogram(rand(20,4))

採用された回答

the cyclist
the cyclist 2016 年 6 月 7 日
編集済み: the cyclist 2016 年 6 月 7 日

As I suggested in this answer, I think the best you can do is to get the bin counts using the histcounts command, and then use the bar command to plot:

Here is an example.

rng 'default'
data1 = randn(20,1);
data2 = randn(30,1);
data3 = randn(40,1);
data4 = randn(50,1);
edges = -4:1:4;
h1 = histcounts(data1,edges);
h2 = histcounts(data2,edges);
h3 = histcounts(data3,edges);
h4 = histcounts(data4,edges);
figure
bar(edges(1:end-1),[h1; h2; h3; h4]')

Just as an FYI, I do think there is good reason to avoid the side-by-side histogram, which is that the bins do not line up where the actual data are, so it can be misleading. I speculate that this is why MathWorks eliminated this option.

その他の回答 (1 件)

Image Analyst
Image Analyst 2016 年 6 月 7 日
It doesn't look like histogram() or histcounts() processes matrices in columns anymore. So you'd have to do the overlapping bars like in the help, rather than the side-by-side bars.

カテゴリ

Help Center および File ExchangeData Distribution Plots についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by