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I keep getting this for my function and I don't know how to fix it -- Undefined function 'symsum' for input arguments of type 'double'.

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Luke Radcliff
Luke Radcliff 2016 年 5 月 29 日
回答済み: VBBV 2023 年 1 月 5 日
This is what have, a pic is also attached of the problem, have to find phi values of n =5,10 and 50
function phi = prob2_6(n)
phi = 13/8 + symsum(((-1).^(n+1)).*factorial(2.*n+1)./factorial(n+2).*factorial(n).*((4).^(2.*n+3)),n,0,n)
return

回答 (2 件)

Image Analyst
Image Analyst 2016 年 5 月 29 日
Can you use sum() instead?
  3 件のコメント
Image Analyst
Image Analyst 2016 年 5 月 29 日
It doesn't know what the ,n,0,n arguments at the end are. What are those used for in symsum()? I don't have the symbolic toolbox so I don't know.
Alex Lisichenko
Alex Lisichenko 2020 年 3 月 17 日
answer is
n = 0:N;
phi = 13/8 + sum(((-1).^(n+1)).*factorial(2.*n+1)./(factorial(n+2).*factorial(n).*((4).^(2.*n+3))))

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VBBV
VBBV 2023 年 1 月 5 日
format long
N = [5 10 50];
Phi = prob2_6(N) % call function by passing vector of values with range N
Phi = 1×3
1.618034154176712 1.618033988674355 1.618033988749895
function phi = prob2_6(N)
for k = 1:length(N)
n = 0:N(k);
phi(k) = 13/8+sum(((-1).^(n+1).*factorial(2.*n+1))./(factorial(n+2).*factorial(n).*(4.^(2.*n+3))));
end
end

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