Number to matrix

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student
student 2012 年 2 月 9 日
編集済み: Cedric 2013 年 10 月 8 日
Hello!
I am very new to MatLab. I am wondering, what is the simplest way to convert a 5-digit number into a matrix of those 5 digits.
Thanks,
  3 件のコメント
student
student 2012 年 2 月 9 日
I want to convert it to integers.
As in, 12345 into [ 1 , 2 , 3 , 4 , 5 ]
Andrei Bobrov
Andrei Bobrov 2012 年 2 月 10 日
:)
fix(rem(TheNumber*10.^-(ceil(log10(TheNumber)):-1:1),1)*10)

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回答 (2 件)

Walter Roberson
Walter Roberson 2012 年 2 月 9 日
sprintf('%d', TheNumber) - '0'
is the simplest, but not the most efficient.

Benjamin Schwabe
Benjamin Schwabe 2012 年 2 月 9 日
You can do that by simply using the following code:
p = 12345; % define your number
pstr=num2str(p);
n=length(pstr);
v=zeros(n,1);
for k=1:n
v(k)=str2double(pstr(k));
end
It will work for all integer numbers. For non Integer numbers, the "." will be transformed into 'NaN'.
  2 件のコメント
Benjamin Schwabe
Benjamin Schwabe 2012 年 2 月 9 日
Maybe some more details:
I convert the number to a string with num2str, then I take each character of the string and transfort it back to a number.
If you want to have a row vector instead of a column, just replace
v=zeros(n,1); by v=zeros(1,n);
Walter Roberson
Walter Roberson 2012 年 2 月 10 日
When you are dealing with single digits, subtracting the character '0' is much more efficient than str2double().

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