how to delete rows from matrix

hello i have 53*3 matrix but include rows that three column of the row are zeros i want to delete the entire row i tried this but since every delete shift the location of the other rows i had problem with the for loop so what can i do to overcome this

[c u]=size(test_ary); %dimensions 
for i=1:c
    for b=1:u
    if(test_ary(i,1)==(o)));
       test_ary(i,:)=[];

end
end
end

Answer 1

[James Tursa]

Replace your for-loop with this vectorized code:

x = all(test_ary==0,2);  % Which rows are all 0's
test_ary(x,:) = [];  % Delete those rows

[m. muner]

not working its give the same matrix

Answer 2

[Jos (10584)]

Using the statement "test_ary(i,:) = []" you will change the size of it, which will cause problems!

tf = all(test_ary==0,2) % true for rows with only 0's
test_ary(tf,:) = [] % remove those rows using logical indexing

[m. muner]

it's work

Answer 3

[Azzi Abdelmalek]

out=test_ary(~ismember(test_ary,[0 0 0],'rows'),:)

[m. muner]

just create new matrix called out which is same as the original test_ary

[Azzi Abdelmalek]

No, this is not true

Answer 4

[Anoire BEN JDIDIA]

I have a big matrix 599794x2 i want to delete rows which contains values which repeats for exemple if A=[1,1;2,1;3,1;4,1;5,2;6,2;7,2]; i want to have A=[1,1;5,2]

[James Tursa]

In the future open up a new Question for this rather than piggyback on an existing Question. But I will answer this here this time:

A = A(logical([1;diff(A(:,2))]),:);

[Anoire BEN JDIDIA]

Hi, Thank you