Adding new circle to plot at constant frequency

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Ali Kareem
Ali Kareem 2016 年 5 月 17 日
編集済み: Robert 2016 年 5 月 18 日
Hello,
I am trying to plot figures that have a circle inside it. I want to add a new circle to the figure at a constant frequency. let us say each 20 steps. For example, if I have 60 steps then I should have 60 figures. Figures from 1 to 20 will have one circle, figures from 21 to 40 will have 2 circles, and figures from 41 to 60 will have three circles. I did that in below code and it is working properly. However, I used if condition in my code. The problem if I will have 1000 steps this mean I need to use (1000/20= 50) if condition and that does not make sense. Is there any sufficient way to do that. This is an example.In my real case, I will have from step 1-20 circle moving at each step from step 21-40 I will have two circles moving and so on. I gave this example to make the situation easy. I have the location (x,y) for all steps stored in one matrix.
function h = circle(x,y,r)
clc;
for i=1:60
figure
if i>=1 && i<20
x=10;
r=0.4;
y=18;
axis ([0 20 0 20])
hold on
th = 0:pi/50:2*pi;
xunit = r * cos(th) + x;
yunit = r * sin(th) + y;
h = plot(xunit, yunit);
hold off
elseif i>=20 && i<40
x=10;
r=0.4;
y=14;
axis ([0 20 0 20])
hold on
th = 0:pi/50:2*pi;
xunit = r * cos(th) + x;
yunit = r * sin(th) + y+2;
h = plot(xunit, yunit);
hold off
hold on
th = 0:pi/50:2*pi;
xunit = r * cos(th) + x;
yunit = r * sin(th) + y;
h = plot(xunit, yunit);
hold off
else i>=40 && i<60;
x=10;
r=0.4;
y=10;
axis ([0 20 0 20])
hold on
th = 0:pi/50:2*pi;
xunit = r * cos(th) + x;
yunit = r * sin(th) + y+4;
h = plot(xunit, yunit);
hold off
hold on
th = 0:pi/50:2*pi;
xunit = r * cos(th) + x;
yunit = r * sin(th) + y+2;
h = plot(xunit, yunit);
hold off
hold on
th = 0:pi/50:2*pi;
xunit = r * cos(th) + x;
yunit = r * sin(th) + y;
h = plot(xunit, yunit);
hold off
end
end
end
Figures that I got is like
and
and
%

採用された回答

Robert
Robert 2016 年 5 月 17 日
編集済み: Robert 2016 年 5 月 18 日
You should put your circle plotting code in a for loop and iterate from 0 to floor(i/20) (or the reverse).
function h = circle % (x,y,r) % shouldn't have these inputs if we don't use them
x = 10;
r = 0.4;
y = 18;
th = 0:pi/50:2*pi;
xunit = r * cos(th) + x;
yunit = r * sin(th) + y;
for ii=1:60 % using ii avoids confusion with complex numbers
figure
axis([0 20 0 20])
for jj = floor(ii/20):-1:0 % backwards to keep colors same as in your example
h = plot(xunit, yunit+2*(jj-1));
hold on
end
hold off
end
end
  2 件のコメント
Ali Kareem
Ali Kareem 2016 年 5 月 17 日
Hi,
Thank you for your reply.
I run code but unfortunately, it does not gave me same results as above and it does not plot figures from 1 to 20
Robert
Robert 2016 年 5 月 18 日
Whoops! floor(ii/20) returns 0 for ii in [0,19]. I should have added 1 or iterated down to zero. I've edited my answer.

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