how to name a figure using a variable name
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I have a figure and want to save this as a tiff or jpeg I have changed a date into variable = 'van190392 15' which I want to use in the file name Such that I get as filename;van190392 15.tiff or van190392 15.jpeg I get an error message, it seems not being allowed/possible
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the cyclist
2016 年 5 月 15 日
編集済み: the cyclist
2016 年 5 月 15 日
variable = 'van190392 15';
figure
plot(rand(3,4))
filename = [variable,'.tif'];
print('-dtiff',filename)
2 件のコメント
the cyclist
2016 年 5 月 22 日
Moved Johannes comment from an "answer" to here. He wrote,
"Thanks for the help, functions great"
Image Analyst
2016 年 5 月 23 日
A related note: To get a figure to have a name you want, instead of like "Figure 1", "Figure 2", etc., you can turn the 'NumberTitle' property 'Off' and set the 'name' property of the figure to a literal string or a string variable:
% Give a name to the title bar/figure.
set(gcf, 'Name', 'Demo by ImageAnalyst', 'NumberTitle', 'Off')
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