Plot data from a cell array in a struct
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Hi everyone,
I want to plot (in a GUI) datas from a cell array. This cell array is contained in a structure, and this structure is stored in the handles.
I have something like:
handles (1x1) > Struct (1xhandles.n) > Data (XXXX*XX cells)
I have a lot of data and I want to plot some columns. I tried this :
for i=1:handles.n
handles.plot(i)=plot(handles.struct(i).data{:,handles.colum+3},handles.struct(i).data{:,handles.colum+1});
end
And this
for i=1:handles.n
handles.plot(i)=plot([handles.struct(i).data{:,handles.colum+3}],[handles.struct(i).data{:,handles.colum+1}]);
end
Both are not working. I get this error msg :
Error using plot
Invalid first data argument
I guess plot can't access values inside the datas cell array.
I succeeded doing this plot by creating a matrice, which store data and then it is quite easy to plot.
for i=1:handles.n
for j=1:lentgh()
X(j,i)=handles.struct(i).data{j,handles.column+3};
Y(j,i)=handles.struct(i).data{j,handles.column+1}
end
handles.plot(i)=plot(X(:,i),Y(:,i));
end
This one works but I'm sure there is a better way of doing this, and a faster too.
Feel free to answer ! Thx.
2 件のコメント
採用された回答
Guillaume
2016 年 4 月 12 日
I would recommend you use a table instead of a cell array. It makes manipulating heterogeneous storage easier.
I get the 'invalid first data argument' error if I pass strings to plot. Are you sure that the data in the columns you want to plot is numeric?
Note that your first syntax is certainly not going to work, but your second should, assuming the data in column + 3 and column + 1 is all scalar or row vectors. Otherwise this will work:
%note that handles.n is probably relevant and should be the same as
%numel(handles.struct)
%in which case get rid of the variable.
for plotnumber = 1 : numel(handles.struct)
handles.plot(plotnumber) = plot(cell2mat(handles.struct(plotnumber).data(:, handles.column + 3)), ...
cell2mat(handles.struct(plotnumber).data(:, handles.column + 1)));
end
Note that if all the cell arrays are the same size, it's probably possible to get rid of the loop.
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