find result from multiple if and range value

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badrul hisham
badrul hisham 2016 年 4 月 10 日
編集済み: Andrei Bobrov 2016 年 4 月 10 日
hello, can someone help me? i have a set of range and i need the number produced from the the range. example: if i input a value of 0.17,it will find 0.17 is in which range (in this case it is in between 0.138 to 0.205) and then it will display the number of that range category which is 6.0
0.0 To 0.068 = 7.0
0.069 To 0.137 = 6.5
0.138 To 0.205 = 6.0
0.206 To 0.274 = 5.5
0.275 To 0.342 = 5.0 .
0.343 To 0.410 = 4.5
0.411 To 0.479 = 4.0
0.480 To 0.547 = 3.5
0.548 To 0.615 = 3.0
0.616 To 0.684 = 2.5
0.685 To 0.752 = 2.0
0.753 To 0.821 = 1.5
0.822 To 0.890 = 1.0

採用された回答

Azzi Abdelmalek
Azzi Abdelmalek 2016 年 4 月 10 日
編集済み: Azzi Abdelmalek 2016 年 4 月 10 日
Edit2
r=[0.0 .068 7.0
0.069 0.137 6.5
0.138 0.205 6.0]
a=0.032
b=mat2cell(r(:,1:2),ones(size(r,1),1),2)
idx=cellfun(@(x) x(1)<=a & x(2)>=a,b)
sprintf('the range of a is %0.1f',r(idx,3))
  5 件のコメント
Azzi Abdelmalek
Azzi Abdelmalek 2016 年 4 月 10 日
Look again at edited answer. I think this is the good one
badrul hisham
badrul hisham 2016 年 4 月 10 日
thank you so much for your help sir. this works perfectly now

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その他の回答 (1 件)

Andrei Bobrov
Andrei Bobrov 2016 年 4 月 10 日
編集済み: Andrei Bobrov 2016 年 4 月 10 日
x =[ 0 7.0000
0.0690 6.5000
0.1380 6.0000
0.2060 5.5000
0.2750 5.0000
0.3430 4.5000
0.4110 4.0000
0.4800 3.5000
0.5480 3.0000
0.6160 2.5000
0.6850 2.0000
0.7530 1.5000
0.8220 1.0000];
t = 0.890;
a = rand(30,1)*t;
[~,~,bin] = histcounts(a,[x(:,1);t]);
out = x(bin,2);

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