find area of region generated using trilateration

hello i have done trilateration in matlab now i want to find out the region generated by trilateration so for that i need vertices of intersection point so help me to find it? its urgent for me thank you.... :)

[Image Analyst]

When you say "i have done trilateration" then exactly what results do you have if it's not the vertices of the triangles? Did you use delaunay()?

https://en.wikipedia.org/wiki/Trilateration

[John D'Errico]

Actually, trilateration is not the same as triangulation.

https://en.wikipedia.org/wiki/Trilateration

It may well be that the OP does not intend to have said trilateration, but that term is well defined. I do wonder which they mean, as often people do not write what they intend. I presume the OP intended to use trilateration by the meaning of the word as it is defined, because the word "intersection" was indeed used.

If so, then one computes the intersection points by some simple algebra. They are intersection points of CIRCLES, with known centers and radii.

Then I can only presume they are asking to compute an area of the region where, for example, 2 or more circles fully overlap. This would most simply done by approximating a set of circular arcs using polygonal segments, then using polyarea.

Some time ago, I briefly debated writing a trilateration code. Not sure how many would have a use for it.

[Image Analyst]

Apparently it's not so urgent since we have not heard from Darshan. So we can catch our breath now and take our time. So "trilateration is the process of determining absolute or relative locations of points by measurement of distances, using the geometry of circles, spheres or triangles" So, are you dealing with circles, spheres, or triangles. For some reason, in your initial rush, you forgot to attach a diagram. Please attach one.

If it's circles and you want the area of overlap, you can use the http://matlab.wikia.com/wiki/FAQ#How_do_I_create_a_circle.3F to make and sum separate circle images and just get the area of the pixels with the greatest value. There are 2 or 3 variants (ways to do it) on that basic idea.